What is the derivative of x^3+3^x ?

The derivative of x^3+3^x is 3x^2+3^xln(3)

What is the first derivative of x^3+3^x ?

The first derivative of x^3+3^x is 3x^2+3^xln(3)

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\frac{d}{d x} (x^{3} + 3^{x})

3 x^{2} + 3^{x} ln (3)

Solution steps

\frac{d}{d x} (x^{3} + 3^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (3^{x})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3^{x}) = 3^{x} ln (3)

= 3 x^{2} + 3^{x} ln (3)

\int sin (x) 2 x d x

n = 0 \sum \infty \frac{1 ^{n}}{3 ^{n}}

x \to 0 - lim (\frac{4}{tan ( x )})

\int e^{- s t} \cdot t d t

\frac{\partial}{\partial y} (x y (\frac{1}{y ^{3}} + 2))

What is the derivative of x^3+3^x ?
The derivative of x^3+3^x is 3x^2+3^xln(3)
What is the first derivative of x^3+3^x ?
The first derivative of x^3+3^x is 3x^2+3^xln(3)