What is (\partial)/(\partial x)((x+2)(y+1)) ?

The answer to (\partial)/(\partial x)((x+2)(y+1)) is y+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial x)((x+2)(y+1))

\frac{\partial}{\partial x} ((x + 2) (y + 1))

y + 1

Solution steps

\frac{\partial}{\partial x} ((x + 2) (y + 1))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (y + 1) \frac{\partial}{\partial x} (x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (y + 1) (\frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (2))

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (2) = 0

= (y + 1) (1 + 0)

Simplify

= y + 1

\frac{d}{d x} (e^{2 x} (2 cos (3 x) + 3 sin (3 x)))

\int_{- 1}^{1} ∣ x ∣ d x

\int x^{2} (2 x^{3} + 3)^{4} d x

x \to 0 lim ((1 + \frac{3}{x ^{2}})^{x})

y^{^{''}} + b^{2} y = 0

What is (\partial)/(\partial x)((x+2)(y+1)) ?
The answer to (\partial)/(\partial x)((x+2)(y+1)) is y+1