What is the derivative of 3x^4+3x ?

The derivative of 3x^4+3x is 12x^3+3

What is the first derivative of 3x^4+3x ?

The first derivative of 3x^4+3x is 12x^3+3

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derivative of

3 x^{4} + 3 x

12 x^{3} + 3

Solution steps

\frac{d}{d x} (3 x^{4} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{4}) + \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (3 x) = 3

= 12 x^{3} + 3

d er i v a t i v e 7 u + 2 u

\int_{0}^{1} 2 x e^{x} d x

\int \frac{cos ^{2} ( x )}{1 + sin ( x )} d x

f (x) = ln (x + 3)

\frac{\partial}{\partial x} (x^{2} (1 + y)^{3})

What is the derivative of 3x^4+3x ?
The derivative of 3x^4+3x is 12x^3+3
What is the first derivative of 3x^4+3x ?
The first derivative of 3x^4+3x is 12x^3+3