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Popular Calculus >

y^'+(2(y-1))/x =0

Solution

y^{^{'}} + \frac{2 ( y - 1 )}{x} = 0

Solution

y = \frac{c _{1}}{x ^{2}} + 1

Solution steps

y^{'} (x) + \frac{2 ( y - 1 )}{x} = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{2}} + 1

y = \frac{c _{1}}{x ^{2}} + 1

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'+(2(y-1))/x =0 ?
The solution for y^'+(2(y-1))/x =0 is y=(c_{1})/(x^2)+1