What is the integral of (10)/(1+x^2) ?

The integral of (10)/(1+x^2) is 10arctan(x)+C

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integral of (10)/(1+x^2)

\int \frac{10}{1 + x ^{2}} d x

10 arctan (x) + C

Solution steps

\int \frac{10}{1 + x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int \frac{1}{1 + x ^{2}} d x

Use the common integral:

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= 10 arctan (x)

Add a constant to the solution

= 10 arctan (x) + C

x \to 0 lim (\frac{arcsin ( 2 x ) - 2 arcsin ( x )}{x ^{3}})

t an g e n t f (x) = x^{2}

2 x^{2} y \frac{d y}{d x} + 1 + 2 x y^{2} = 0

\frac{\partial}{\partial x} (x y + \frac{27}{x})

\frac{d}{d x} (e^{5 x + πi})

What is the integral of (10)/(1+x^2) ?
The integral of (10)/(1+x^2) is 10arctan(x)+C