What is the first derivative of-x+4 ?

The first derivative of-x+4 is -1

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derivative of-x+4

\frac{d}{d x} (- x + 4)

- 1

Solution steps

\frac{d}{d x} (- x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d x}{d x} + \frac{d}{d x} (4)

\frac{d x}{d x} = 1

\frac{d}{d x} (4) = 0

= - 1 + 0

Simplify

= - 1

x \to - 1 + lim (x^{2})

\int (x + 1)^{2} e^{x} d x

\int \frac{1}{2 x + 4} d x

\frac{d}{d x} (ln (ln (x^{2 x})))

\int \frac{27}{x ( x ^{2} + 4 ) ^{2}} d x