What is the derivative of tan(cos(2x)) ?

The derivative of tan(cos(2x)) is -2sec^2(cos(2x))sin(2x)

What is the first derivative of tan(cos(2x)) ?

The first derivative of tan(cos(2x)) is -2sec^2(cos(2x))sin(2x)

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\frac{d}{d x} (tan (cos (2 x)))

- 2 sec^{2} (cos (2 x)) sin (2 x)

Solution steps

\frac{d}{d x} (tan (cos (2 x)))

Apply the chain rule:

sec^{2} (cos (2 x)) \frac{d}{d x} (cos (2 x))

= sec^{2} (cos (2 x)) \frac{d}{d x} (cos (2 x))

\frac{d}{d x} (cos (2 x)) = - sin (2 x) \cdot 2

= sec^{2} (cos (2 x)) (- sin (2 x) \cdot 2)

Simplify

= - 2 sec^{2} (cos (2 x)) sin (2 x)

(1 + ln (x) + \frac{y}{x}) d x = (8 - ln (x)) d y

\int \frac{e ^{x}}{1 + 9 e ^{2 x}} d x

\frac{d}{d x} (- 262144 cos (2 x))

x \to 3 lim (\frac{x ^{2}}{x - 3})

x \to 2 + lim (\frac{4}{x})

What is the derivative of tan(cos(2x)) ?
The derivative of tan(cos(2x)) is -2sec^2(cos(2x))sin(2x)
What is the first derivative of tan(cos(2x)) ?
The first derivative of tan(cos(2x)) is -2sec^2(cos(2x))sin(2x)