taylor x^2-4,0

Lösung

taylor

x^{2} - 4, 0

- 4 + x^{2}

Schritte zur Lösung

Apply the Taylor Formula

= - 4 + \frac{\frac{d}{d x} ( x ^{2} - 4 ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( x ^{2} - 4 ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( x ^{2} - 4 ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= - 4 + \frac{0}{1 !} x + \frac{2}{2 !} x^{2} + \frac{0}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{0}{9 !} x^{9} + \frac{0}{10 !} x^{10}

Fasse zusammen

= - 4 + x^{2}

\frac{d}{d x} (\frac{3 e ^{x}}{5 e ^{x} + 4})

t an g e n t f (x) = - \frac{3}{x ^{2} - 4}, (1, 1)

\frac{d}{d x} (ln (1 + ln (x)))

\int (\frac{1}{x \cdot ( 5 - x )}) d x

x \to 0 + lim (1 + csc (x))