What is the derivative of 4x^2-x^3 ?

The derivative of 4x^2-x^3 is 8x-3x^2

What is the first derivative of 4x^2-x^3 ?

The first derivative of 4x^2-x^3 is 8x-3x^2

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\frac{d}{d x} (4 x^{2} - x^{3})

8 x - 3 x^{2}

Solution steps

\frac{d}{d x} (4 x^{2} - x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) - \frac{d}{d x} (x^{3})

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (x^{3}) = 3 x^{2}

= 8 x - 3 x^{2}

\int 6 x^{- 3} d x

\int (x^{2} + 1) x d x

d er i v a t i v e y = (2 x^{3} + 7)^{2}

a re a x^{3}, x^{\frac{1}{3}}, [0, 2]

\frac{d}{d x} (\frac{x - 1}{x + 3})

What is the derivative of 4x^2-x^3 ?
The derivative of 4x^2-x^3 is 8x-3x^2
What is the first derivative of 4x^2-x^3 ?
The first derivative of 4x^2-x^3 is 8x-3x^2