What is the tangent of f(x)= 1/(2+3x),(2, 1/8) ?

The tangent of f(x)= 1/(2+3x),(2, 1/8) is y=-3/64 x+7/32

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tangent of f(x)= 1/(2+3x),(2, 1/8)

tangent

y = - \frac{3}{64} x + \frac{7}{32}

Solution steps

Find the slope of

f (x) = \frac{1}{2 + 3 x} : \frac{df ( x )}{d x} = - \frac{3}{( 2 + 3 x ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{3}{64}

Find the line with slope m=

- \frac{3}{64}

and passing through

(2, \frac{1}{8}) : y = - \frac{3}{64} x + \frac{7}{32}

y = - \frac{3}{64} x + \frac{7}{32}

What is the tangent of f(x)= 1/(2+3x),(2, 1/8) ?
The tangent of f(x)= 1/(2+3x),(2, 1/8) is y=-3/64 x+7/32