What is area y=e^x,y=e^{-3x},x=-2,x=1 ?

The answer to area y=e^x,y=e^{-3x},x=-2,x=1 is e+(e^9-2e^3+3e+1)/(3e^3)-2

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area y=e^x,y=e^{-3x},x=-2,x=1

area

e + \frac{e ^{9} - 2 e ^{3} + 3 e + 1}{3 e ^{3}} - 2

Decimal

134.67981 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{1} e^{x} - e^{- 3 x} d x

Solve

\int_{- 2}^{1} e^{x} - e^{- 3 x} d x : e + \frac{e ^{9} - 2 e ^{3} + 3 e + 1}{3 e ^{3}} - 2

The area is:

= e + \frac{e ^{9} - 2 e ^{3} + 3 e + 1}{3 e ^{3}} - 2

What is area y=e^x,y=e^{-3x},x=-2,x=1 ?
The answer to area y=e^x,y=e^{-3x},x=-2,x=1 is e+(e^9-2e^3+3e+1)/(3e^3)-2