derivative of 7e^x+2/(\sqrt[3]{x})

Lösung

\frac{d}{d x} (7 e^{x} + \frac{2}{3 x})

7 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

Schritte zur Lösung

\frac{d}{d x} (7 e^{x} + \frac{2}{3 x})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (7 e^{x}) + \frac{d}{d x} (\frac{2}{3 x})

\frac{d}{d x} (7 e^{x}) = 7 e^{x}

\frac{d}{d x} (\frac{2}{3 x}) = - \frac{2}{3 x ^{\frac{4}{3}}}

= 7 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

\int_{0}^{π} sec^{2} (x) d x

d er i v a t i v e y = 8 arcsin (\frac{x}{4}) - \frac{x 16 - x ^{2}}{2}

\frac{\partial}{\partial x} (e^{y} cos (x))

\frac{d}{d x} (\frac{1}{1 + x + x ^{2}})

l a pl a ce t r an s f or m e^{- 2 t} sin (t)