What is the derivative of (x^3/6) ?

The derivative of (x^3/6) is (x^2)/2

What is the first derivative of (x^3/6) ?

The first derivative of (x^3/6) is (x^2)/2

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\frac{d}{d x} (\frac{x ^{3}}{6})

\frac{x ^{2}}{2}

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{6})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{6} \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{6} \cdot 3 x^{3 - 1}

Simplify

\frac{1}{6} \cdot 3 x^{3 - 1} : \frac{x ^{2}}{2}

= \frac{x ^{2}}{2}

y^{^{''}} + 9 y = 18

n = 1 \sum \infty \frac{15 n !}{n ^{n}}

\frac{\partial}{\partial x} (2 x + 3 y + 6 x y e^{3 x^{2} y})

x \to - 1 lim (- 6)

d er i v a t i v e 9 x - (sin^{2} (2 x))

What is the derivative of (x^3/6) ?
The derivative of (x^3/6) is (x^2)/2
What is the first derivative of (x^3/6) ?
The first derivative of (x^3/6) is (x^2)/2