What is the solution for y^'+3x^2y=sin(x)e^{-x^3},y(0)=1 ?

The solution for y^'+3x^2y=sin(x)e^{-x^3},y(0)=1 is y=-(cos(x))/(e^{x^3)}+2/(e^{x^3)}

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y^'+3x^2y=sin(x)e^{-x^3},y(0)=1

y^{^{'}} + 3 x^{2} y = sin (x) e^{- x^{3}}, y (0) = 1

y = - \frac{cos ( x )}{e ^{x^{3}}} + \frac{2}{e ^{x^{3}}}

Solution steps

y^{'} (x) + 3 x^{2} y = sin (x) e^{- x^{3}}

Solve linear ODE:

y = - \frac{cos ( x )}{e ^{x^{3}}} + \frac{2}{e ^{x^{3}}}

y = - \frac{cos ( x )}{e ^{x^{3}}} + \frac{2}{e ^{x^{3}}}

d er i v a t i v e x^{3} b^{5} + y^{4} b + z^{6}

\int_{0}^{10} 100 e^{0.1 x} d x

y^{^{''}} - 2 y^{^{'}} - 3 y = - 3 x e^{- x}

x \to 0 lim (x^{3} cos (\frac{1}{x}))

t an g e n t - 5 x^{\frac{1}{2}} + x^{\frac{3}{2}}

What is the solution for y^'+3x^2y=sin(x)e^{-x^3},y(0)=1 ?
The solution for y^'+3x^2y=sin(x)e^{-x^3},y(0)=1 is y=-(cos(x))/(e^{x^3)}+2/(e^{x^3)}