What is the solution for xy^'+y=-6xy^2,y(1)=9 ?

The solution for xy^'+y=-6xy^2,y(1)=9 is y= 9/(x(54ln(x)+1))

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xy^'+y=-6xy^2,y(1)=9

x y^{^{'}} + y = - 6 x y^{2}, y (1) = 9

y = \frac{9}{x ( 54 ln ( x ) + 1 )}

Solution steps

x y^{'} (x) + y = - 6 x y^{2}

Solve Bernoulli ODE:

y = \frac{9}{x ( 54 ln ( x ) + 1 )}

y = \frac{9}{x ( 54 ln ( x ) + 1 )}

t an g e n t f (x) = \frac{1}{x}, at x = 4

\int sin (x) e^{c o s (x)} d x

\int_{0}^{1} 5 x^{2} d x

l a pl a ce t r an s f or m 31

t an g e n t y = 3 x^{3} - x^{2} + 3, (2, 23)

What is the solution for xy^'+y=-6xy^2,y(1)=9 ?
The solution for xy^'+y=-6xy^2,y(1)=9 is y= 9/(x(54ln(x)+1))