What is the derivative of sqrt(2x-9) ?

The derivative of sqrt(2x-9) is 1/(sqrt(2x-9))

What is the first derivative of sqrt(2x-9) ?

The first derivative of sqrt(2x-9) is 1/(sqrt(2x-9))

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\frac{d}{d x} (2 x - 9)

\frac{1}{2 x - 9}

Solution steps

\frac{d}{d x} (2 x - 9)

Apply the chain rule:

\frac{1}{2 2 x - 9} \frac{d}{d x} (2 x - 9)

= \frac{1}{2 2 x - 9} \frac{d}{d x} (2 x - 9)

\frac{d}{d x} (2 x - 9) = 2

= \frac{1}{2 2 x - 9} \cdot 2

Simplify

\frac{1}{2 2 x - 9} \cdot 2 : \frac{1}{2 x - 9}

= \frac{1}{2 x - 9}

\int (x - 1)^{\frac{1}{2}} d x

\int sin (y) cosh (x) d y

\int \frac{- ( x ^{2} - 1 ) ( 6 x ^{2} + 6 )}{x ^{2} + 1} d x

\int \frac{1}{0.15 x + 20} d x

f (n) = 2^{n}

What is the derivative of sqrt(2x-9) ?
The derivative of sqrt(2x-9) is 1/(sqrt(2x-9))
What is the first derivative of sqrt(2x-9) ?
The first derivative of sqrt(2x-9) is 1/(sqrt(2x-9))