What is the derivative of x^{1/3}+2x ?

The derivative of x^{1/3}+2x is 1/(3x^{2/3)}+2

What is the first derivative of x^{1/3}+2x ?

The first derivative of x^{1/3}+2x is 1/(3x^{2/3)}+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d x} (x^{\frac{1}{3}} + 2 x)

\frac{1}{3 x ^{\frac{2}{3}}} + 2

Solution steps

\frac{d}{d x} (x^{\frac{1}{3}} + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{\frac{1}{3}}) + \frac{d}{d x} (2 x)

\frac{d}{d x} (x^{\frac{1}{3}}) = \frac{1}{3 x ^{\frac{2}{3}}}

\frac{d}{d x} (2 x) = 2

= \frac{1}{3 x ^{\frac{2}{3}}} + 2

\int_{0}^{9} x d x

y^{^{''}} + 4 y = t - 2 sin (2 t)

\frac{d}{d x} (\frac{( x - 1 )}{x + 1})

x \to \infty lim (\frac{x ^{2} - 9}{2 x - 6})

y^{^{''}} - 8 y^{^{'}} + 16 y = e^{4 x}

What is the derivative of x^{1/3}+2x ?
The derivative of x^{1/3}+2x is 1/(3x^{2/3)}+2
What is the first derivative of x^{1/3}+2x ?
The first derivative of x^{1/3}+2x is 1/(3x^{2/3)}+2