y^{''}+9y^'=40e^{1t}

Lösung

y^{^{''}} + 9 y^{^{'}} = 40 e^{1 t}

y = c_{1} + c_{2} e^{- 9 t} + 4 e^{t}

Schritte zur Lösung

y^{''} (t) + 9 y^{'} (t) = 40 e^{1 t}

Solve linear ODE:

y = c_{1} + c_{2} e^{- 9 t} + 4 e^{t}

y = c_{1} + c_{2} e^{- 9 t} + 4 e^{t}

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