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Popular Calculus >

integral from 1 to 2 of (x^2-4)

Solution

\int_{1}^{2} (x^{2} - 4) d x

Solution

- \frac{5}{3}

+1

Decimal

- 1.66666 \dots

Solution steps

\int_{1}^{2} x^{2} - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x^{2} d x - \int_{1}^{2} 4 d x

\int_{1}^{2} x^{2} d x = \frac{7}{3}

\int_{1}^{2} 4 d x = 4

= \frac{7}{3} - 4

Simplify

\frac{7}{3} - 4 : - \frac{5}{3}

= - \frac{5}{3}

Graph

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t an g e n t f (x) = x^{2} + 3 x + 5, (1, 9)

limit as x approaches 2+of 1/(|2-x|)

x \to 2 + lim (\frac{1}{∣ 2 - x ∣})

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\int_{0}^{\frac{π}{6}} sin^{4} (6 x) d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (x^2-4) ?
The integral from 1 to 2 of (x^2-4) is -5/3