What is the integral from 1 to 3 of (4x^3-3x^2) ?

The integral from 1 to 3 of (4x^3-3x^2) is 54

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 1 to 3 of (4x^3-3x^2)

\int_{1}^{3} (4 x^{3} - 3 x^{2}) d x

54

Solution steps

\int_{1}^{3} 4 x^{3} - 3 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 4 x^{3} d x - \int_{1}^{3} 3 x^{2} d x

\int_{1}^{3} 4 x^{3} d x = 80

\int_{1}^{3} 3 x^{2} d x = 26

= 80 - 26

Simplify

= 54

in v erse l a pl a ce \frac{1}{s ^{2} + s}

n = 1 \sum \infty - \frac{1}{n ^{2}}

d er i v a t i v e x^{10 x}

d er i v a t i v e 3 x + 10

\int (- \frac{1}{5} sec (1 - 5 x)) d x

What is the integral from 1 to 3 of (4x^3-3x^2) ?
The integral from 1 to 3 of (4x^3-3x^2) is 54