What is laplacetransform cos(t-(2pi)/3) ?

The answer to laplacetransform cos(t-(2pi)/3) is (-s+sqrt(3))/(2(s^2+1))

laplacetransform cos(t-(2pi)/3)

laplace transform

cos (t - \frac{2 π}{3})

\frac{- s + 3}{2 ( s ^{2} + 1 )}

Solution steps

L {cos (t - \frac{2 π}{3})}

Use Laplace Transform table:

L {cos (a t + b)} = \frac{s \cdot cos ( b ) - a \cdot sin ( b )}{s ^{2} + a ^{2}}

L {cos (t - \frac{2 π}{3})} = \frac{s cos ( - \frac{2 π}{3} ) - 1 \cdot sin ( - \frac{2 π}{3} )}{s ^{2} + 1 ^{2}}

= \frac{s cos ( - \frac{2 π}{3} ) - 1 \cdot sin ( - \frac{2 π}{3} )}{s ^{2} + 1 ^{2}}

= \frac{- s + 3}{2 ( s ^{2} + 1 )}

\int \frac{x - 3}{8 x - x ^{2}} d x

d er i v a t i v e y = \frac{x + \frac{1}{x}}{2 x + \frac{1}{x}}

d er i v a t i v e f (x) = arctan (\frac{x - 1}{x + 1})

\frac{\partial}{\partial x} (ln (x^{2} y^{2}))

\int \frac{x ^{2} + 1}{x} d x

What is laplacetransform cos(t-(2pi)/3) ?
The answer to laplacetransform cos(t-(2pi)/3) is (-s+sqrt(3))/(2(s^2+1))