What is area y=sqrt(3x),x=0,x=4 ?

The answer to area y=sqrt(3x),x=0,x=4 is (16)/(sqrt(3))

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area y=sqrt(3x),x=0,x=4

area

y = 3 x, x = 0, x = 4

\frac{16}{3}

Decimal

9.23760 \dots

Solution steps

Apply the area formula:

\int_{0}^{4} 3 x d x

Solve

\int_{0}^{4} 3 x d x : \frac{16}{3}

The area is:

= \frac{16}{3}

x d y - y d x = 2 x^{2} y^{2} d y, y (1) = 2

\frac{d}{d x} (cos (2 x) cos (x))

\int \frac{8 - 3 x}{25 - 64 x ^{2}} d x

d er i v a t i v e (x - 3) (x^{2} + 6)

\frac{\partial}{\partial x} (8 x cos (x) cos (y))

What is area y=sqrt(3x),x=0,x=4 ?
The answer to area y=sqrt(3x),x=0,x=4 is (16)/(sqrt(3))