What is the solution for (dy)/(dt)-(2t)/(1+t^2)y=3 ?

The solution for (dy)/(dt)-(2t)/(1+t^2)y=3 is y=3arctan(t)(1+t^2)+c_{1}(1+t^2)

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(dy)/(dt)-(2t)/(1+t^2)y=3

\frac{d y}{d t} - \frac{2 t}{1 + t ^{2}} y = 3

y = 3 arctan (t) (1 + t^{2}) + c_{1} (1 + t^{2})

Solution steps

\frac{d y}{d t} - \frac{2 t}{1 + t ^{2}} y = 3

Solve linear ODE:

y = 3 arctan (t) (1 + t^{2}) + c_{1} (1 + t^{2})

y = 3 arctan (t) (1 + t^{2}) + c_{1} (1 + t^{2})

d er i v a t i v e tan^{2} (y)

\frac{\partial}{\partial x} (2 x^{3} + 3 y^{2} - 5 x y)

\int \frac{2 x}{( x - 1 ) ^{2}} d x

\int_{- π}^{π} sin^{101} (x) d x

\frac{d}{d x} (sec (5 x + 2))

What is the solution for (dy)/(dt)-(2t)/(1+t^2)y=3 ?
The solution for (dy)/(dt)-(2t)/(1+t^2)y=3 is y=3arctan(t)(1+t^2)+c_{1}(1+t^2)