What is the derivative of (x^3^5) ?

The derivative of (x^3^5) is 15x^{14}

What is the first derivative of (x^3^5) ?

The first derivative of (x^3^5) is 15x^{14}

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\frac{d}{d x} ((x^{3})^{5})

15 x^{14}

Solution steps

\frac{d}{d x} ((x^{3})^{5})

Simplify

(x^{3})^{5} : x^{15}

= \frac{d}{d x} (x^{15})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 15 x^{15 - 1}

Simplify

= 15 x^{14}

n = 0 \sum \infty 1 + \frac{1}{n}

y^{^{'}} - \frac{y}{x} = x

\frac{d}{d x} (- 5 e^{- x})

\int \frac{1}{8 x + 1} d x

\int \frac{5 x ^{2} - x - 3}{x ^{2} ( x + 1 )} d x

What is the derivative of (x^3^5) ?
The derivative of (x^3^5) is 15x^{14}
What is the first derivative of (x^3^5) ?
The first derivative of (x^3^5) is 15x^{14}