What is the derivative of 9x^2-2x+1 ?

The derivative of 9x^2-2x+1 is 18x-2

What is the first derivative of 9x^2-2x+1 ?

The first derivative of 9x^2-2x+1 is 18x-2

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\frac{d}{d x} (9 x^{2} - 2 x + 1)

18 x - 2

Solution steps

\frac{d}{d x} (9 x^{2} - 2 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9 x^{2}) - \frac{d}{d x} (2 x) + \frac{d}{d x} (1)

\frac{d}{d x} (9 x^{2}) = 18 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 18 x - 2 + 0

Simplify

= 18 x - 2

\frac{d}{d x} (x a^{2} + x^{2})

a re a x = y^{2} - 1, x = 1 - y^{2}

in v erse l a pl a ce \frac{2}{s ^{2} ( s + 2 )}

\int \frac{16 x}{8 x ^{2} + 1} d x

\int sin (7 t) d t

What is the derivative of 9x^2-2x+1 ?
The derivative of 9x^2-2x+1 is 18x-2
What is the first derivative of 9x^2-2x+1 ?
The first derivative of 9x^2-2x+1 is 18x-2