What is the sum from n=1 to infinity of (3^n)/(n^3) ?

The sum from n=1 to infinity of (3^n)/(n^3) is diverges

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sum from n=1 to infinity of (3^n)/(n^3)

n = 1 \sum \infty \frac{3 ^{n}}{n ^{3}}

diverges

Solution steps

n = 1 \sum \infty \frac{3 ^{n}}{n ^{3}}

Apply Series Ratio Test:

diverges

= diverges

\int_{0}^{1} 7 x x^{2} + 9 d x

\int \frac{x ^{2} + 1}{( x - 7 ) ( x - 6 )} d x

\int \frac{e ^{2 t}}{1 + e ^{4 t}} d t

\frac{\partial}{\partial y} (e^{x - y})

y \to \infty lim (\frac{2 y ^{2} - 3 y + 5}{y ^{2} - 5 y + 2})

What is the sum from n=1 to infinity of (3^n)/(n^3) ?
The sum from n=1 to infinity of (3^n)/(n^3) is diverges