What is the derivative of ln(e^{2x}) ?

The derivative of ln(e^{2x}) is 2

What is the first derivative of ln(e^{2x}) ?

The first derivative of ln(e^{2x}) is 2

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derivative of

ln (e^{2 x})

2

Solution steps

\frac{d}{d x} (ln (e^{2 x}))

Simplify

ln (e^{2 x}) : 2 x

= \frac{d}{d x} (2 x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= 2 \cdot 1

Simplify

= 2

\int \frac{1}{a} d a

s im pl i f y \frac{4 x ^{3} + 3 x ^{2}}{x}

x \to 1 lim (3 \cdot a + x)

\int \frac{1}{( 121 + x ^{2} ) ^{\frac{3}{2}}} d x

\int \frac{( 2 x ^{2} - x + 4 )}{x ^{3} + 4 x} d x

What is the derivative of ln(e^{2x}) ?
The derivative of ln(e^{2x}) is 2
What is the first derivative of ln(e^{2x}) ?
The first derivative of ln(e^{2x}) is 2