What is the derivative of ln(3x^2+4) ?

The derivative of ln(3x^2+4) is (6x)/(3x^2+4)

What is the first derivative of ln(3x^2+4) ?

The first derivative of ln(3x^2+4) is (6x)/(3x^2+4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d x} (ln (3 x^{2} + 4))

\frac{6 x}{3 x ^{2} + 4}

Solution steps

\frac{d}{d x} (ln (3 x^{2} + 4))

Apply the chain rule:

\frac{1}{3 x ^{2} + 4} \frac{d}{d x} (3 x^{2} + 4)

= \frac{1}{3 x ^{2} + 4} \frac{d}{d x} (3 x^{2} + 4)

\frac{d}{d x} (3 x^{2} + 4) = 6 x

= \frac{1}{3 x ^{2} + 4} \cdot 6 x

Simplify

\frac{1}{3 x ^{2} + 4} \cdot 6 x : \frac{6 x}{3 x ^{2} + 4}

= \frac{6 x}{3 x ^{2} + 4}

\frac{d}{d x} (24 x^{\frac{3}{2}})

s im pl i f y \frac{2 x}{x ^{2} + 1}

f (x) = x 2

\int \frac{( ln ( z ) ) ^{6}}{z} d z

\frac{d ^{2}}{d x ^{2}} (cos (x^{2}))

What is the derivative of ln(3x^2+4) ?
The derivative of ln(3x^2+4) is (6x)/(3x^2+4)
What is the first derivative of ln(3x^2+4) ?
The first derivative of ln(3x^2+4) is (6x)/(3x^2+4)