derivative y=(6t-3)/(5t+8)

Lösung

ableitung von

y = \frac{6 t - 3}{5 t + 8}

\frac{63}{( 5 t + 8 ) ^{2}}

Schritte zur Lösung

\frac{d}{d t} (\frac{6 t - 3}{5 t + 8})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d t} ( 6 t - 3 ) ( 5 t + 8 ) - \frac{d}{d t} ( 5 t + 8 ) ( 6 t - 3 )}{( 5 t + 8 ) ^{2}}

\frac{d}{d t} (6 t - 3) = 6

\frac{d}{d t} (5 t + 8) = 5

= \frac{6 ( 5 t + 8 ) - 5 ( 6 t - 3 )}{( 5 t + 8 ) ^{2}}

Multipliziere aus

6 (5 t + 8) - 5 (6 t - 3) : 63

= \frac{63}{( 5 t + 8 ) ^{2}}

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n = 3 \sum \infty (\frac{e}{π})^{n}

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in v erse l a pl a ce \frac{1}{( s ^{2} + 4 ) ( s ^{2} + 1 )}

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