What is (\partial)/(\partial x)(-sin(xy)) ?

The answer to (\partial)/(\partial x)(-sin(xy)) is -cos(xy)y

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(\partial)/(\partial x)(-sin(xy))

\frac{\partial}{\partial x} (- sin (x y))

- cos (x y) y

Solution steps

\frac{\partial}{\partial x} (- sin (x y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{\partial}{\partial x} (sin (x y))

Apply the chain rule:

cos (x y) \frac{\partial}{\partial x} (x y)

= cos (x y) \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x y) = y

= - cos (x y) y

\int \frac{x}{( x ^{2} - 1 )} d x

\int 8 x^{2} ln (x) d x

\frac{d}{d t} (sin (t) + cos (t))

a re a y = x^{3}, (- 1, 2)

\int (x^{3} + x)^{2} d x

What is (\partial)/(\partial x)(-sin(xy)) ?
The answer to (\partial)/(\partial x)(-sin(xy)) is -cos(xy)y