What is the tangent of e^x,\at x=5 ?

The tangent of e^x,\at x=5 is y=e^5x-4e^5

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tangent of e^x,\at x=5

tangent of

e^{x}, at x = 5

y = e^{5} x - 4 e^{5}

Solution steps

Find the tangent point:

(5, e^{5})

Find the slope of

y = e^{x} : \frac{d y}{d x} = e^{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = e^{5}

Find the line with slope m=

e^{5}

and passing through

(5, e^{5}) : y = e^{5} x - 4 e^{5}

y = e^{5} x - 4 e^{5}

\frac{d}{d x} ((3 x - 1)^{5})

d er i v a t i v e sin (2 x) cos (3 x)

\int x^{2} e^{x} cos (x) d x

\int 2 x cos (x^{2}) d x

\int_{- 1}^{2} (3 x^{2} - 2 x + 3) d x