derivative of 2^x+cos(3x)

Lösung

\frac{d}{d x} (2^{x} + cos (3 x))

2^{x} ln (2) - sin (3 x) \cdot 3

Schritte zur Lösung

\frac{d}{d x} (2^{x} + cos (3 x))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2^{x}) + \frac{d}{d x} (cos (3 x))

\frac{d}{d x} (2^{x}) = 2^{x} ln (2)

\frac{d}{d x} (cos (3 x)) = - sin (3 x) \cdot 3

= 2^{x} ln (2) - sin (3 x) \cdot 3

\int \frac{sin ( 2 x )}{47 + cos ^{2} ( x )} d x

(3 x)^{^{'}}

\frac{\partial}{\partial x} (y^{2} cos (y))

\int \frac{5 x}{4 x + 2} d x

x \to - 2 lim (x^{3} + 4 x^{2} - 5 x + 1)