What is (\partial)/(\partial z)(zsqrt(x^2+y^2)) ?

The answer to (\partial)/(\partial z)(zsqrt(x^2+y^2)) is sqrt(x^2+y^2)

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(\partial)/(\partial z)(zsqrt(x^2+y^2))

\frac{\partial}{\partial z} (z x^{2} + y^{2})

x^{2} + y^{2}

Solution steps

\frac{\partial}{\partial z} (z x^{2} + y^{2})

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{2} + y^{2} \frac{\partial}{\partial z} (z)

Apply the common derivative:

\frac{\partial}{\partial z} (z) = 1

= x^{2} + y^{2} \cdot 1

Simplify

= x^{2} + y^{2}

\frac{\partial}{\partial y} (x^{2} + 2 x y)

\int y^{4} d y

in v erse l a pl a ce \frac{x ^{2} + 3}{2}

\int (sec (t) - 1)^{2} d t

a re a y = x^{3}, [0, 4]

What is (\partial)/(\partial z)(zsqrt(x^2+y^2)) ?
The answer to (\partial)/(\partial z)(zsqrt(x^2+y^2)) is sqrt(x^2+y^2)