(\partial)/(\partial y)(3x+2ysin(x))

Lösung

\frac{\partial}{\partial y} (3 x + 2 y sin (x))

2 sin (x)

Schritte zur Lösung

\frac{\partial}{\partial y} (3 x + 2 y sin (x))

Behandle

x

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x) + \frac{\partial}{\partial y} (2 y sin (x))

\frac{\partial}{\partial y} (3 x) = 0

\frac{\partial}{\partial y} (2 y sin (x)) = 2 sin (x)

= 0 + 2 sin (x)

Vereinfache

= 2 sin (x)

x \to 20 lim (sin (70 - x))

f (x) = (2 x^{4} - 1) (5 x^{3} + 6 x)

d er i v a t i v e \frac{( x ^{2} - 5 ) ^{3}}{x ^{2} + 2}

x \to 5 lim (ln (x^{2} - 25))

\int 5 e^{x} - cos (x) + 3 x^{2} - \frac{1}{x} d x