y^{''}+4y=4sin(2x)

Lösung

y^{^{''}} + 4 y = 4 sin (2 x)

y = c_{1} cos (2 x) + c_{2} sin (2 x) - x cos (2 x)

Schritte zur Lösung

y^{''} (x) + 4 y = 4 sin (2 x)

Solve linear ODE:

y = c_{1} cos (2 x) + c_{2} sin (2 x) - x cos (2 x)

y = c_{1} cos (2 x) + c_{2} sin (2 x) - x cos (2 x)

t an g e n t y = x^{2} + 3, (1, 4)

\frac{d}{d x} (\frac{x ^{p (x)}}{x ^{m} - a ^{m}})

\frac{\partial}{\partial x} (\frac{( x + y )}{y ^{2} - x})

\frac{d}{d x} (\frac{1 + csc ( x ^{7} )}{1 - cot ( x ^{7} )})

d er i v a t i v e \frac{9}{x - 6}