What is the solution for y^'= x/(200)-y/(100) ?

The solution for y^'= x/(200)-y/(100) is y=(x-100)/2+(c_{1})/(e^{x/(100))}

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y^'= x/(200)-y/(100)

y^{^{'}} = \frac{x}{200} - \frac{y}{100}

y = \frac{x - 100}{2} + \frac{c _{1}}{e ^{\frac{x}{100}}}

Solution steps

y^{'} (x) = \frac{x}{200} - \frac{y}{100}

Solve linear ODE:

y = \frac{x - 100}{2} + \frac{c _{1}}{e ^{\frac{x}{100}}}

y = \frac{x - 100}{2} + \frac{c _{1}}{e ^{\frac{x}{100}}}

ma c l a u r in 2^{x}

\int y sin (x) d x

x \to π lim (sin (\frac{7}{6} x))

\int (x^{3} + 1)^{2} d x

d er i v a t i v e \frac{( x ^{2} - 2 x + 3 )}{( x - 1 ) ^{2}}

What is the solution for y^'= x/(200)-y/(100) ?
The solution for y^'= x/(200)-y/(100) is y=(x-100)/2+(c_{1})/(e^{x/(100))}