What is the limit as x approaches 0 of tan(2x)csc(4x) ?

The limit as x approaches 0 of tan(2x)csc(4x) is 1/2

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limit as x approaches 0 of tan(2x)csc(4x)

x \to 0 lim (tan (2 x) csc (4 x))

\frac{1}{2}

Decimal

0.5

Solution steps

x \to 0 lim (tan (2 x) csc (4 x))

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 0 - lim (tan (2 x) csc (4 x)) = \frac{1}{2}

x \to 0 + lim (tan (2 x) csc (4 x)) = \frac{1}{2}

= \frac{1}{2}

x \to π lim (\frac{5 x}{3})

\int y^{2} e^{- y} d y

\frac{d}{d x} (x^{3} - 3 x^{2} + 2 x)

l a pl a ce t r an s f or m e^{- 2 t} sin (3 t)

\int x csc^{2} (x) d x

What is the limit as x approaches 0 of tan(2x)csc(4x) ?
The limit as x approaches 0 of tan(2x)csc(4x) is 1/2