integral from 0 to 1 of 8x^3

Lösung

\int_{0}^{1} 8 x^{3} d x

2

Schritte zur Lösung

\int_{0}^{1} 8 x^{3} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{0}^{1} x^{3} d x

Wende die Potenzregel an

= 8 [\frac{x ^{4}}{4}]_{0}^{1}

Berechne die Grenzen:

\frac{1}{4}

= 8 \cdot \frac{1}{4}

Vereinfache

= 2

t an g e n t f (x) = \frac{1}{x ^{2}}, at x = - 1

x \to \infty lim (ln (5))

\int_{0}^{x} \frac{1}{x} d x

\frac{d}{d x} (9 cos^{2} (x))

x \to - 1 + lim (x + 4)