en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Calculus >

derivative of arcsec(4x)

Solution

derivative of

arcsec (4 x)

Solution

\frac{1}{x ^{2} 16 x ^{2} - 1}

Solution steps

\frac{d}{d x} (arcsec (4 x))

Apply the chain rule:

\frac{1}{( 4 x ) ^{2} ( 4 x ) ^{2} - 1} \frac{d}{d x} (4 x)

= \frac{1}{( 4 x ) ^{2} ( 4 x ) ^{2} - 1} \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= \frac{1}{( 4 x ) ^{2} ( 4 x ) ^{2} - 1} \cdot 4

Simplify

\frac{1}{( 4 x ) ^{2} ( 4 x ) ^{2} - 1} \cdot 4 : \frac{1}{x ^{2} 16 x ^{2} - 1}

= \frac{1}{x ^{2} 16 x ^{2} - 1}

Graph

Popular Examples

derivative of f(x)=2x+7

d er i v a t i v e f (x) = 2 x + 7

(x+y)dx-(x+y-2)dy=0

(x + y) d x - (x + y - 2) d y = 0

derivative of (x^2-1(x^2+1))

\frac{d}{d x} ((x^{2} - 1) (x^{2} + 1))

integral of tsec^2(2t)

\int t sec^{2} (2 t) d t

(\partial)/(\partial y)(y/((x+y)^2))

\frac{\partial}{\partial y} (\frac{y}{( x + y ) ^{2}})

Frequently Asked Questions (FAQ)

What is the derivative of arcsec(4x) ?
The derivative of arcsec(4x) is 1/(sqrt(x^2)\sqrt{16x^2-1)}
What is the first derivative of arcsec(4x) ?
The first derivative of arcsec(4x) is 1/(sqrt(x^2)\sqrt{16x^2-1)}