y^'+y=e^x,y(0)=6

Lösung

y^{^{'}} + y = e^{x}, y (0) = 6

y = \frac{e ^{x}}{2} + \frac{11}{2 e ^{x}}

Schritte zur Lösung

y^{'} (x) + y = e^{x}

Solve linear ODE:

y = \frac{e ^{x}}{2} + \frac{11}{2 e ^{x}}

y = \frac{e ^{x}}{2} + \frac{11}{2 e ^{x}}

\frac{\partial}{\partial x} (\frac{x}{x ^{5} - y ^{5}})

\int sin (x) csc (x) d x

f (x) = e^{2 x^{2}}

\int sin^{2} (3 x) cos^{3} (3 x) d x

x \to 0 lim (5 - x^{2})