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Popular Calculus >

xy^'+y=e^x,y(1)=1

Solution

x y^{^{'}} + y = e^{x}, y (1) = 1

Solution

y = \frac{e ^{x}}{x} + \frac{1 - e}{x}

Solution steps

x y^{'} (x) + y = e^{x}

Solve linear ODE:

y = \frac{e ^{x}}{x} + \frac{1 - e}{x}

y = \frac{e ^{x}}{x} + \frac{1 - e}{x}

Graph

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derivative of f(x)= x/((x-1)^2)

d er i v a t i v e f (x) = \frac{x}{( x - 1 ) ^{2}}

\frac{d}{d t} (ln (2 t))

Frequently Asked Questions (FAQ)

What is the solution for xy^'+y=e^x,y(1)=1 ?
The solution for xy^'+y=e^x,y(1)=1 is y=(e^x)/x+(1-e)/x