What is the sum from n=0 to infinity of (-3/4)^{n-1} ?

The sum from n=0 to infinity of (-3/4)^{n-1} is converges

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sum from n=0 to infinity of (-3/4)^{n-1}

n = 0 \sum \infty (- \frac{3}{4})^{n - 1}

converges

Solution steps

n = 0 \sum \infty (- \frac{3}{4})^{n - 1}

Apply Series Ratio Test:

converges

= converges

\int 2 θ cos (θ) d θ

x \to \infty lim (3 (1 + \frac{2}{x}) - x)

\frac{d}{d x} (- \frac{8}{x ^{3}} + \frac{2}{x ^{2}})

\int \frac{e ^{a r c t a n (x)} + 1}{1 + x ^{2}} d x

x \to - 1 - lim (\frac{x}{∣ x - 1 ∣})

What is the sum from n=0 to infinity of (-3/4)^{n-1} ?
The sum from n=0 to infinity of (-3/4)^{n-1} is converges