derivative f(x)=x^2-3x+1

Lösung

ableitung von

f (x) = x^{2} - 3 x + 1

2 x - 3

Schritte zur Lösung

\frac{d}{d x} (x^{2} - 3 x + 1)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (1) = 0

= 2 x - 3 + 0

Vereinfache

= 2 x - 3

\int (\frac{x + 6}{x ^{2} + 11 x + 18}) d x

\frac{d}{d x} (x^{6} + 3 x^{4} + 7 x^{2})

l a pl a ce t r an s f or m cos (π t)

x \to 0 lim ((x^{2}) cos (\frac{8}{x}))

\frac{\partial}{\partial x} (- 10 x y sin (x y^{2}))