What is the derivative of 1-cos(3x) ?

The derivative of 1-cos(3x) is 3sin(3x)

What is the first derivative of 1-cos(3x) ?

The first derivative of 1-cos(3x) is 3sin(3x)

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\frac{d}{d x} (1 - cos (3 x))

3 sin (3 x)

Solution steps

\frac{d}{d x} (1 - cos (3 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (cos (3 x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (cos (3 x)) = - sin (3 x) \cdot 3

= 0 - (- sin (3 x) \cdot 3)

Simplify

= 3 sin (3 x)

x \to - 4 - lim (x + 4)

\int sec^{2} (x) d x

\frac{d}{d x} (\frac{x}{1 - ln ( x - 7 )})

x \to - 2 + lim (\frac{x ^{2}}{x + 2})

\frac{\partial}{\partial x} (x^{9} y^{9} - x^{8} y^{8})

What is the derivative of 1-cos(3x) ?
The derivative of 1-cos(3x) is 3sin(3x)
What is the first derivative of 1-cos(3x) ?
The first derivative of 1-cos(3x) is 3sin(3x)