What is the solution for (y^2+9)dx-1/((2x-5)^2)dy=0 ?

The solution for (y^2+9)dx-1/((2x-5)^2)dy=0 is y=3tan(4x^3-30x^2+75x-c_{1})

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(y^2+9)dx-1/((2x-5)^2)dy=0

(y^{2} + 9) d x - \frac{1}{( 2 x - 5 ) ^{2}} d y = 0

y = 3 tan (4 x^{3} - 30 x^{2} + 75 x - c_{1})

Solution steps

(y^{2} + 9) d x - \frac{1}{( 2 x - 5 ) ^{2}} d y = 0

Solve separable ODE:

y = 3 tan (4 x^{3} - 30 x^{2} + 75 x - c_{1})

y = 3 tan (4 x^{3} - 30 x^{2} + 75 x - c_{1})

\frac{d}{d x} (11)

\int e^{c o s (t)} sin (2 t) d t

\frac{d}{d x} (\frac{1}{6} ln (e^{2 x} - e^{x} + 1))

d er i v a t i v e x h (x)

in v erse l a pl a ce \frac{1}{s ^{2} ( s ^{2} + 2 ^{2} )}

What is the solution for (y^2+9)dx-1/((2x-5)^2)dy=0 ?
The solution for (y^2+9)dx-1/((2x-5)^2)dy=0 is y=3tan(4x^3-30x^2+75x-c_{1})