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人気のある微分積分 >

integral of (x^3)/(x^2-16)

解

\int \frac{x ^{3}}{x ^{2} - 16} d x

解

\frac{1}{2} (x^{2} - 16 + 16 ln x^{2} - 16) + C

解答ステップ

\int \frac{x ^{3}}{x ^{2} - 16} d x

u置換積分法を適用する

= \int \frac{u + 16}{2 u} d u

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{u + 16}{u} d u

拡張

\frac{u + 16}{u} : 1 + \frac{16}{u}

= \frac{1}{2} \cdot \int 1 + \frac{16}{u} d u

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int 1 d u + \int \frac{16}{u} d u)

\int 1 d u = u

\int \frac{16}{u} d u = 16 ln ∣ u ∣

= \frac{1}{2} (u + 16 ln ∣ u ∣)

代用を戻す

u = x^{2} - 16

= \frac{1}{2} (x^{2} - 16 + 16 ln x^{2} - 16)

定数を解答に追加する

= \frac{1}{2} (x^{2} - 16 + 16 ln x^{2} - 16) + C

グラフ

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