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Popular Calculus >

xy^'-2y=x^2-x-2

Solution

x y^{^{'}} - 2 y = x^{2} - x - 2

Solution

y = x^{2} ln (x) + x + 1 + c_{1} x^{2}

Solution steps

x y^{'} (x) - 2 y = x^{2} - x - 2

Solve linear ODE:

y = x^{2} ln (x) + x + 1 + c_{1} x^{2}

y = x^{2} ln (x) + x + 1 + c_{1} x^{2}

Graph

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y^{^{''}} - 2 y^{^{'}} - 15 y = e^{(3 x)} cos (2 x)

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\int \frac{( 1 - z )}{z z} d z

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Frequently Asked Questions (FAQ)

What is the solution for xy^'-2y=x^2-x-2 ?
The solution for xy^'-2y=x^2-x-2 is y=x^2ln(x)+x+1+c_{1}x^2