What is (\partial)/(\partial x)(2y-x) ?

The answer to (\partial)/(\partial x)(2y-x) is -1

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(\partial)/(\partial x)(2y-x)

\frac{\partial}{\partial x} (2 y - x)

- 1

Solution steps

\frac{\partial}{\partial x} (2 y - x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 y) - \frac{\partial}{\partial x} (x)

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (x) = 1

= 0 - 1

Simplify

= - 1

d er i v a t i v e cos (\frac{1 - e ^{8 x}}{1 + e ^{8 x}})

x \to 7 lim (\frac{4}{( x - 7 ) ^{2}})

t a y l or 2 x e^{- 4 x}

\int 1 - \frac{1}{x ^{2}} d x

\int 7 x^{2} e^{6 x} d x

What is (\partial)/(\partial x)(2y-x) ?
The answer to (\partial)/(\partial x)(2y-x) is -1