What is the solution for (9y^2-xy)dx+(x^2)dy=0 ?

The solution for (9y^2-xy)dx+(x^2)dy=0 is y= x/(9ln(x)+c_{1)}

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(9y^2-xy)dx+(x^2)dy=0

(9 y^{2} - x y) d x + (x^{2}) d y = 0

y = \frac{x}{9 ln ( x ) + c _{1}}

Solution steps

(9 y^{2} - x y) d x + (x^{2}) d y = 0

Solve Bernoulli ODE:

y = \frac{x}{9 ln ( x ) + c _{1}}

y = \frac{x}{9 ln ( x ) + c _{1}}

\int \frac{x ^{3}}{x ^{2} + 9} d x

d er i v a t i v e 4^{- 3} (\frac{2}{s ^{7}} + 3 s)^{4}

\int \frac{2 x + 3}{x ^{2} + 1} d x

im pl i c i t \frac{d y}{d x}, 1 = (\frac{y}{x})

d er i v a t i v e f (x) = 8 cos (t)

What is the solution for (9y^2-xy)dx+(x^2)dy=0 ?
The solution for (9y^2-xy)dx+(x^2)dy=0 is y= x/(9ln(x)+c_{1)}