What is the sum from k=1 to infinity of (k^3)/(5^k) ?

The sum from k=1 to infinity of (k^3)/(5^k) is converges

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sum from k=1 to infinity of (k^3)/(5^k)

k = 1 \sum \infty \frac{k ^{3}}{5 ^{k}}

converges

Solution steps

k = 1 \sum \infty \frac{k ^{3}}{5 ^{k}}

Apply Series Ratio Test:

converges

= converges

\int \frac{7 sin ( x ) + 2 sec ( x )}{tan ( x )} d x

in v erse l a pl a ce \frac{s}{2 s + 4}

\frac{\partial}{\partial x} (\frac{5}{x y} + \frac{x}{y} + \frac{y}{x})

\frac{d}{d x} (x^{3} + x^{2} - 5 x)

\int x \cdot e^{5 x} d x

What is the sum from k=1 to infinity of (k^3)/(5^k) ?
The sum from k=1 to infinity of (k^3)/(5^k) is converges